A wire had a resistance of 20 ohm. It was then melted and reduced to one fifth of it's original length and it's cross section area was doubled. Find its new resistance.
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A wire had a resistance of 20 ohm. It was then melted and reduced to one fifth of it's original length and it's cross section area was doubled. Find its new resistance.
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Answer:
Explanation:
R = ρ* L/A
R ∝ L And R ∝ 1/A
here, length is reduced to 1/5 times so resistance also reduced to 1/5 times
so, resistance is 20/5 Ω = 4 Ω
Again, Area is doubled so resistance get half.
so, New resistance is 4/2Ω = 2Ω
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Amrit
Explanation:
4/2 omega is the right answer that is 2 omega.When we divide 4 by 2 we get 2