A wire is 1m long, 0.2mm in diameter and has a resistance of 10ohm. Calculate the resistivity of its material? With full explanation
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A wire is 1m long, 0.2mm in diameter and has a resistance of 10ohm. Calculate the resistivity of its material? With full explanation
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d = 0.2mm = 0.2×10^-3m = 2×10^-4m
=> r = 1×10^-4 m
L = 1m
A = πr²
= 3.14×(1×10^-4)²
= 3.14×10^(-8) m²
R = 10 ohms
resistivity = R×A/L
= 10×3.14×10^(-8)/1
= 3.14×10^(-7) ohm m
Hey there!
Given,
Length(l) = 1 m
Diameter(d) = 0.2 mm
Radius(r) = 0.1 mm or 0.001 m
Resistance(R) = 10 Ω
Now,
Area =πr²
= 3.14 × 0.001 × 0.001
= 0.00000314 m²
We know,
Resistivity = RA/l
= 10 × 0.00000314/1
= 0.0000314 Ω m
= 3.14×10^-7 Ω m
Hope It Helps You!