A wire of length 68 cm is bent in the form of a rectangle such that its length is 6 cm more than its breadth. Find the length and breadth of the rectangle so formed.
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A wire of length 68 cm is bent in the form of a rectangle such that its length is 6 cm more than its breadth. Find the length and breadth of the rectangle so formed.
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Answer:
68=2(l+b)
68=2(x+6+x)
68=4x+12
68-12=4x
56=4x
X=14
Therefore length=20
Breadth=14
Step-by-step explanation:
hey buddy,
here is your answer..
let the breadth be (x)cm
and length is equal to (x+6)cm
perimeter of rectangle = 68cm
2(l+b) = 68cm
2(x+6+x) = 68cm
2(2x+6) = 68
2x+6 = 34
2x = 34-6
x = 28÷2
x = 14cm
breadth = x = 14cm
length = x+6 = 14+6 = 20cm
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