A)300 rev
B)600 rev
C)200 rev
D)900 rev
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A)300 rev
B)600 rev
C)200 rev
D)900 rev
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Answer:
Heya!!
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→Given,
W° = 1800 rpm = 1800/60 =30 rotations
W=0
time = 20sec
so, apply
w =w° + alpha t
0= 30 + alpha × 20
alpha =-3/2 rotations /sec
( NOTE →
∆ = angular displacement here)
∆ = W° t + 1/2 alpha t^2
∆ = 30 × 20 + 1/2 (-3/2) × 20 ×20
∆ = 600-300
= 300 rotations
correct answer is option( 1)
hope it helps!