A(6 1) B(8 2) and C(9 4) are three vertices of a parallelogram ABCD. If E is the mid point of DC. Find the area of the ∆ADE
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A(6 1) B(8 2) and C(9 4) are three vertices of a parallelogram ABCD. If E is the mid point of DC. Find the area of the ∆ADE
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Answer:
The area of ADE is 0.75 unit².
Step-by-step explanation:
A(6 1) B(8 2) and C(9 4) are three vertices of a parallelogram ABCD.
Area of triangle ABC is
ABCD is a parallelogram. E is mid point of DC.
Here AC is the diagonal of ABCD. It means AC divides the area of parallelogram in two equal parts.
E is the mid point of DC. It means AE is median of ACD and divide the area of triangle ACD in two equal parts.
Therefore the area of ADE is 0.75 unit².