abc and ADC are two equilateral triangle on a common base ac . find the angle of the resulting quadrilateral. show that it is a rhombus.
plss..answer..soon..!!
with full explanation..!!
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abc and ADC are two equilateral triangle on a common base ac . find the angle of the resulting quadrilateral. show that it is a rhombus.
plss..answer..soon..!!
with full explanation..!!
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Answer:
hey mate
Step-by-step explanation:
ΔABC and ΔADC are two equilateral triangles on a common base AC.
In triangle ABC, AB=AC=BC and in triangle ADC, AD=AC=DC
From this we get two triangles ABC and ADC are Equilateral Triangles with same side.
The equilateral triangle have some angle which is equal to 60°
Here AC is the common base, we get a quadrilateral ABCD.
<A=60°+60°= 120°, <B=60°, <C=60°+60°=120° and <D=60°
Also AB=BC=CD=AD
All the sides of this quadrilateral are equal , so it is a rhombus
Answer:
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