∆ABC ∼ ∆ DEC. AB = 20, AC=48 and BC: CE = 2:3. Then CD=?
please answe I will give 10 points to you.
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∆ABC ∼ ∆ DEC. AB = 20, AC=48 and BC: CE = 2:3. Then CD=?
please answe I will give 10 points to you.
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Step-by-step explanation:
triangle ABC ~ triangle DEC -----( Given )
Here AB = 20 , AC = 48 , BC : CE = 2 : 3, CD =?
The correspounding sides are proportional
AB / DE = BC / EC = AC / DC
20 / DE = 2 / 3 = 48 / DC
From ratio 2 , 3 we have
48 / Dc = 2 / 3
taking cross product we have
Dc × 2 = 48 × 3
DC = ( 48 × 3 ) / 2
DC = 24 × 3
DC = 72