ABC is an isosceles triangle with AB = AC. Draw AP parallel to BC to show that angle B = angle C.
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ABC is an isosceles triangle with AB = AC. Draw AP parallel to BC to show that angle B = angle C.
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Question:
ABC is an isosceles triangle with AB = AC. Draw AP parallel to BC to show that angle B = angle C.
Given:
Since △ ABC is isosceles
We know AB = AC
Given that AP is parallel to AC ,
So, ∠APB = ∠APC = 90°
To prove: ∠B = ∠C
To note
My symbols or letter may differ as i dont have a exact copy of your triangle.
Answer:
∠APB = ∠APC = 90°