After5years fathers ege will be three times his sons age, while5years ago fathers agewas 7times his sons age find their preasent age.
After5years fathers ege will be three times his sons age, while5years ago fathers agewas 7times his sons age find their preasent age.
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Answer:
father's age 40 & son-s age 10
Step-by-step explanation:
Let the father present age =x years and son present age =y years
According to the first condition
5 years later father will be (x+5) years old and son will be (y+5) years old.
⇒x+5=3(y+5)
⇒x+5=3y+15⇒x=3y+10....eq1
According to the second condition
5 years ago father was (x−5) years old and son was (y−5) years old.
⇒x−5=7(y−5)
⇒x−5=7y−35
⇒x−7y=−30....eq2
Put the value of x from eq1
⇒3y+10−7y=−30⇒−4y=−40⇒y=10
Put y=10 in eq1
⇒x=3×10+10=40
Hence, Father present age =40 years
Son present age =10 years
Step-by-step explanation:
Father's age Sons age
5yrs ago 7x x
present age 7x+5 x+5
5yrs hence 7x+10 x+10
3times sons age = fathers age
3(x+10)= 7x+10
3x + 30=7x+10
30 -10=7x-3x
20 = 4x
x= 5
Present age of son is 10 yrs and Father's is 40 yrs