Ages of two people different by 16 years if six year ago the elder one was three times as old as the younger one find their present ages.
With proper explanation or will be reported
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Ages of two people different by 16 years if six year ago the elder one was three times as old as the younger one find their present ages.
With proper explanation or will be reported
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Verified answer
Given:
Find:
Their present ages.
Solution:
Let the present age of the Elder person be x years and the present age of the Younger person be y years.
Then, the difference of their ages is:
x-y = 16.
x - y - 16 = 0. → Equation 1.
6 years ago, their ages are x-6 and y-6 respectively.
Also, it is given that:
x-6 = 3(y-6).
x-6 = 3y - 18.
x - 3y + 12 = 0. → Equation 2.
Equation 1 - Equation 2:
2y - 28 =0.
2y = 28.
y = 14.
Substituting the value of y in Equation 1:
x-(14) = 16.
x = 16+14.
x = 30.
∴ The present ages of the Elder person and Younger person are 30 and 14 years respectively.