Aluminium reacts with chlorine gas to form aluminium chloride: 2Al + Cl2 2AlCl3 Determine the limiting reagent if 34 gm of aluminium reacts with 39 gm of chlorine, also find the amount of aluminium chloride formed.
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Aluminium reacts with chlorine gas to form aluminium chloride: 2Al + Cl2 2AlCl3 Determine the limiting reagent if 34 gm of aluminium reacts with 39 gm of chlorine, also find the amount of aluminium chloride formed.
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Answer:
Answer : Aluminium atom is limiting reagent and 10 more atoms will be required.
Solution :
The balanced reaction is,
2Al+3Cl_2arrow 2AlCl_32Al+3Cl
2
arrow2AlCl
3
According to the reaction, 2 atoms of aluminium react with 3 molecules of chlorine gas which means that 6 atoms of chlorine.
(1) Then 20 atoms of aluminum react with :
\frac{6}{2}\times 20=60
2
6
×20=60 atoms of chlorine
60 atoms of chlorine = \frac{60}{2}=30
2
60
=30 molecules of chlorine gas
(2) Now 45 molecules of chlorine gas will react with :
Number of atoms of chlorine in 45 molecules of chlorine gas = 90 atoms
Now 90 atoms of chlorine will react with : \frac{2}{6}\times 90=30
6
2
×90=30 atoms of aluminium
From this we conclude that the aluminum is a limiting reagent and the chlorine is an excess reagent.
Number of aluminium atoms required = Number of aluminium required to consume chlorine - number of aluminium atoms given
Number of aluminium atoms required = 30 - 20 = 10 atoms of aluminium atoms.