An air bubble of volume 3mL is released at the bottom of a water tank of height 20 feet. Calculate the volume of the bubble when it reaches the surface of water. (Atmospheric pressure 75 cm Hg). Please write the formula also.
An air bubble of volume 3mL is released at the bottom of a water tank of height 20 feet. Calculate the volume of the bubble when it reaches the surface of water. (Atmospheric pressure 75 cm Hg). Please write the formula also.
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Answer:
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Explanation:
We can assume that the process is isothermal because the temperature of the surrounding remains constant
So, by applying Boyle’s law
P
s
V
s
=P
d
V
d
.....(I)
Where, s = surface of water
d = depth
Given that,
Depth of lake =h
Volume V
s
=3V
d
Now,
P
s
=75cmHg
P
d
=75+
10
h
Now, put the value of equation(I)
75×3=75+
10
h
225−75=
10
h
h=1500cm
h=15m
Hence, the depth of lake is 15 m