An angle is 32 more than one half of its complement .find the angle in degrees.
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Verified answer
Let x is one anglex=(90-x)/2 +32
x-32=(90-x)/2
2x-64= 90-x
3x=90+64=154
x=154/3 and second (90-154/3)=(270-154)/3
=116/3
hence 154/3 and 116/3 are two angles
Verified answer
Let the complement be xThen the angle = 1/2x + 32
A/Q,
x + 1/2x + 32 = 90 ..........since the angles are complementary
(2x + x)/2 = 90 - 32
3/2x = 58
x = 58 x 2/3
x = 116/3°
The required angle = 1/2 x 116/3 + 32 = 58/3 + 32 = 154/3°