an athlete completes one round of a circular track of diameter 200 m in 40 seconds what will be the distance covered and the displacement at the end of 2 minutes and 20 seconds
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an athlete completes one round of a circular track of diameter 200 m in 40 seconds what will be the distance covered and the displacement at the end of 2 minutes and 20 seconds
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HELLO
TOTAL TIME TAKEN= 2 MINS 20 SECONDS
= 2 ×60 +20 SEC
=140 SECS
NOW , IN 40 SECS NO OF ROUNDS MADE = 1
IN 140 SECS NO OF ROUND MADE = 1/40×140 = 3.5 ROUNDS
MAGNITUDE OF DISPLACEMENT AT THE END OF 2 MIN AND 20 SECOND WILL BE
AC WHOLE SQUARE = AB WHOLE SQUARE
+ BC WHOLE SQUARE
AC WHOLE SQUARE = 10 WHOLE SQUARE +10 WHOLE SQUARE
AC = √200 = 14.143 M ETRE
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