An electric bulb draws a current of .8 A and works on 250 V on the average 8 hours a day. a. Find the power consumed by the bulb b. If the electric distribution company changes Rs 5 for 6 KWH, what is the monthly bill for 60 days
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An electric bulb draws a current of .8 A and works on 250 V on the average 8 hours a day. a. Find the power consumed by the bulb b. If the electric distribution company changes Rs 5 for 6 KWH, what is the monthly bill for 60 days
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An electric bulb draws s current of B.A and works on 250 V on the average 8 hours a day.
Find the power consumed by the bulb
if the electric distribution company charges Rs 5 for 6 KWH, what is the monthly bill for 60 days.
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Solution
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Hint:Use the formula of Power, P = VI
Step 1: Note the given values
Potential difference, V=250V
Current, I =8A
Step 2: Finding the power consumed by Bulb
Power, P= VI
Putting the values in formula:
P=250×8
P=2000watts
Bulb works on the average of 8 hours a day.
So, Power consumed in one day:
P=2000×8
P=16000Wh = 16000kWh
Hence, Power Consumed in one day is 16kWh
Step 2: Finding the monthly bill electricity.
We know that:
Power Consumed in one day is 16kWh
Power Consumed in 60 days = 60×16 kWh = 960kWh
As given,
Bill for 6kWh = Rs. 5
So, Bill for 960kWh =
6
5
×960
=
6
5
×960
= Rs. 800.
So, Bill for 1 month =
2
800
= Rs. 400
Hence, monthly bill for electricity is Rs. 400.