An electric dipole consists of charges +q and –q at separation x. At distance d(d >> x) on equatorial position of dipole, the field is proportional to
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An electric dipole consists of charges +q and –q at separation x. At distance d(d >> x) on equatorial position of dipole, the field is proportional to
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electric field due to dipole at equatorial line is proportional to x.
It has given that an electric dipole consists of charges +q and -q at seperation x. at distance (d >> x) on equatorial position of dipole, the field is proportional to ....
let a point P is point of observation seperated d distance apart from the midpoint of dipole axis. and also +q is placed at A and -q is placed at B.
now electric field due to +q at a point P, E₁ = kq/[√(d² + x²/4)]² along AP
electric field due to -q at a point P, E₂ = Kq/[√(d² + x²/4)]² along PB
net electric field due to dipole at equatorial line, E = E₁cosΦ + E₂cosΦ
= kq/[√(d² + x²/4)]² × (x/2)/√(d² + x²/4) + kq/[√(d² + x²/4)]² × (x/2)/√(d² + x²/4)
= kqx/(d² + x²/4)³/²
as d >> x so, d² >> x²/4
so, E = kqx/d³
therefore, electric field due to dipole at equatorial line is proportional to x.
Answer:
electric field at equitorial is proportional to x
Explanation: