An electric heater of power 100W raises the temperature of 5kg of a liquid from 25⁰C to 31⁰C in 2 minutes. Calculate the specific heat capacity of the liquid
Please solve it ASAP
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An electric heater of power 100W raises the temperature of 5kg of a liquid from 25⁰C to 31⁰C in 2 minutes. Calculate the specific heat capacity of the liquid
Please solve it ASAP
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Answer:
400J/Kg.℃
Explanation:
power P =100w
mass m=5kg
time T=2min=120 sec
Change in temperature ∆T =6℃
specific heat s= Q/m.∆T
Power P= i2R
Heat Q= i2Rt = P×t
therefore Q= 100×120/5×6=400J/kg.℃