an electric iron of resistance 20 takes a current of 5a calculate the heat developed in 30 second(5marks)
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an electric iron of resistance 20 takes a current of 5a calculate the heat developed in 30 second(5marks)
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Explanation:
R=20 ohm
I=5A
T=30sec
Heat=H=I^2RT
H=(5)^2*20*30
H=25*20*30
H=15000
H=15KJ