An electric iron of resistance 20om takes a current of 5 A. Calculate the heat developed in
30 s.
please tell correct
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An electric iron of resistance 20om takes a current of 5 A. Calculate the heat developed in
30 s.
please tell correct
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(R) = 20 Ω
(I)= 5 A
(t)= 30 s
Now we know that H= I2Rt
use it here = 5×5×20×30
= 15000J=1.5×104J
The heat developed in 30s is 1.5×104J.
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Explanation:
H=I²Rt
H= 5²*20*30
H= 25*600
H= 15000j
H= 1.5*10⁴j