an elevator descends into a mine shaft at the rate of 6 metre per minute. if it descends start from 10 metre above the ground level how long will it take to reach the shaft 350 below the ground level?
an elevator descends into a mine shaft at the rate of 6 metre per minute. if it descends start from 10 metre above the ground level how long will it take to reach the shaft 350 below the ground level?
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Answer:
Step-by-step explanation:
Starting position of mine shaft is = 10m above ground
but,
it moves in opposite direction so it travels the distance (-350 m ) below the ground.
Total distance covered by mine shaft = 10m - (-350m)
= 10 + 350
= 360m
Now, taken to cover a distance of 6m by it = 1 minute
Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min
6
1
min
Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \
6
1
× 360 = 60 min
60 minutes = 1 hour
thus, in one hour the mine shaft reaches = 350 below the ground.
Answer:
this would help for sure