an exterior angle of a triangle is measure 110 degree and one of the interior angle 40 degree.find the measure of all angles of the triangle.
an exterior angle of a triangle is measure 110 degree and one of the interior angle 40 degree.find the measure of all angles of the triangle.
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Answer:
Its an isosceles triangle
Step-by-step explanation:
let a triangle abc and an exterior angle acd=110 and angle abc=40 degree
as we know the sum of opposite interior angle =exterior angle
so,
40 degree+angle bac=110 degree
angle bac=110-40=70degree
now,
sum of all angles of a triangle=180 degree
angle (a+b+bca)=180
(40+70+bca)=180
angle bca =180-110=70
therefor,
angle a=70degree,angle b=40 degree(given)and angle bca=70 degree