an insect climbs 2 cm up a slippery rod in 1 second and slips down by 1 cm over the next second how many second will the insect take to reach the top of the rod 15 cm high? And ans is 27sec but how??
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an insect climbs 2 cm up a slippery rod in 1 second and slips down by 1 cm over the next second how many second will the insect take to reach the top of the rod 15 cm high? And ans is 27sec but how??
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Answer:
30 sec
Step-by-step explanation:
Here,
insect climb up in 1 second = 2 cm
insect slips down in next second = 1 cm
so ,
distance traveled by him in 2 seconds = 1 cm
or,
time taken to climb 1 cm = 2 second
so,
time taken to climb 15 cm = 2*15
= 30 seconds.
it may be useful.
Solution : In 1 second an insect climb up 2 cm.
In next second an insect slips by 1 cm.
Total distance covered in 2 seconds is 2-1=1 cm.
We have to find in how many second will the insect take to reach the top of the rod 15 cm high.
i.e. An insect take to climb 1 cm distance = 2 seconds
An insect take to climb 15 cm distance = seconds
An insect take to climb 15 cm distance = 30 seconds.
Therefore, 30 seconds will the insect take to reach the top of the rod 15 cm high.