an inverted cone of height 10 cm and base radius 6.4 cm contains water to a depth of 5 cm, measured from the vertex. calculate the volume of water in the cone
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an inverted cone of height 10 cm and base radius 6.4 cm contains water to a depth of 5 cm, measured from the vertex. calculate the volume of water in the cone
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Answer:
r of big cone =6.4cm
h=10cm
Depth of water in that cone =5cm
Acc. To statement they must be similar triangles.
Because{ h of big cone }/depth of water =2/1
So r/R=2/1
So ,R of small cone =3.2cm
We have to find the vol. Of small cone i.e.
==== 1/3 πr^2h
=1/3 ×22/7×3.2 ×3.2 ×5
=1/3×22/7×51.2
=1126.4/21
=53.638cm^3
So, vol. Of water left in cone =53.63cm^3