An isosceles triangle has an area of 8cm^2.Find the length of its altitude.
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Area of triangle= 1/2 b×h
Let b=h=y
1/2×y×y=8
y^2=16
y=4
Perpendicular=base=4
Now by Pythagoras theorem
4^2+4^2= √16+16=√32=4√2
So length of the altitude is 4√2.
Hope it helps......