An obje a of mass
m and velocity v has kinetic energyof 200 J
Find the new kinetic
energy if the
mass of the
object becomes
double
& velocity still remains
the same?
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An obje a of mass
m and velocity v has kinetic energyof 200 J
Find the new kinetic
energy if the
mass of the
object becomes
double
& velocity still remains
the same?
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Answer:
the kinetic energy become double
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{Correct \: QuEstion...}}}}}}[/tex]
⋆ An object of mass,m and velocity,v has kinetic energy as 200 J. Find the new kinetic energy if the mass of the object becomes double and velocity still remains the same.
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{GivEn \: That...}}}}}}[/tex]
⋆ An object of mass m and velocity v has kinetic energy as 200 Joules.
★ Situations regards this question are mentioned below:
⋆ The mass of the object becomes double.
⋆ Velocity still remains the same.
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{To \: FiNd...}}}}}}[/tex]
⋆ The new kinetic energy is the mass of the object becomes double.
⋆ The new kinetic energy is the velocity still remains the same.
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{SoluTion...}}}}}}[/tex]
⋆ The new kinetic energy is the mass of the object becomes double = 400 Joules
⋆ The new kinetic energy is the velocity still remains the same = 400 Joules
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{Using \: ConcEpt...}}}}}}[/tex]
⋆ Formula to find out the kinetic energy =
[tex]{\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}}[/tex]
[tex]{\large{\pmb{\sf{\bigstar \:{\underline{Full \; SoluTion...}}}}}}[/tex]
[tex]{\underline{\sf{According \: to \: Situation \: 1)}}}[/tex]
[tex]{\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf 200 \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf 200 \times 2 = 1 \: mv^{2} \\ \\ :\implies \sf 400= 1 \: mv^{2} \\ \\ :\implies \sf 400= mv^{2} \\ \\ :\implies \sf mv^{2} = 400[/tex]
Henceforth, we get mv² as 400
[tex]{\underline{\sf{According \: to \: Situation \: 2)}}}[/tex]
~ Now as it's given that the mass of the object becomes double(2) and velocity still remains the same.
[tex]{\small{\underline{\boxed{\sf{K.E \: = \dfrac{1}{2} mv^{2}}}}}} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} mv^{2} \\ \\ :\implies \sf K.E \: = \dfrac{1}{2} \: 2mv^{2} \\ \\ :\implies \sf K.E \: = \dfrac{1}{\cancel{2}} \: \cancel{2}mv^{2} \\ \\ :\implies \sf K.E \: = 1 \: mv^{2} \\ \\ :\implies \sf K.E \: = mv^{2} \\ \\ :\implies \sf K.E \: = 400 \: Joules[/tex]
Henceforth, the new kinetic energy is the mass of the object becomes double and the new kinetic energy is the velocity still remains the same is 400 Joules