an object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm what is the focal length of the mirror what is the position of image.
Share
an object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm what is the focal length of the mirror what is the position of image.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Height of object h1=2 cm
Height of real image h2=−3 cm
Magnification m=h2h1=−32=−1.5
We know that, m=−vu
Here, object distance u=−16cm
Substituting the value, we get
−1.5=−v(16)⇒1.5=v16⇒=16×(−1.5)=−24c
The position of image is 24 cm in front of the mirror (negative sign indicates that the image is. on the left side of the mirror).
Answer:
Here h
1
= 2 cm, u = -16 cm, h
2
= -3 cm (Since image is real and inverted.)
∵m=
h
1
h
2
=−
u
v
∴v=
h
1
−h
2
u=
2
3
×(−16)=−24cm
f
1
=
v
1
+
u
1
=−
24
1
−
16
1
=
48
−2−3
=
48
−5
;f=
5
−48
=−9.6cm
Explanation:
Hi