. An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. What is the position of the image? *
2 points
24 cm
-24 cm
30 cm
-30 cm
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. An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. What is the position of the image? *
2 points
24 cm
-24 cm
30 cm
-30 cm
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Answer:
Explanation:
Correct Question,
An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. What is the position of the image?
Solution,
Here, we have
Height of the object, h₁ = 2 cm
Height of the image, H₂ = - 3 cm
Object distance, u = - 16 cm
To Find,
Image distance, v = ?
According to the magnification formula
We know that
m = h₂/h₁ = - v/u
So, putting all the values, we get
⇒ m = h₂/h₁ = - v/u
⇒ - 3/2 = - v/- 16
⇒ - 3 × (- 16) = 2 × (- v)
⇒ v = - 48/2
⇒ v = - 24 cm
Hence, the image distance is - 24 cm.
Here, - 24 cm is the correct option.