an object 5 cm in length is placed 25cm away from from a converging lens of focal length 10cm draw the ray diagram and find position size and nature of image formed
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an object 5 cm in length is placed 25cm away from from a converging lens of focal length 10cm draw the ray diagram and find position size and nature of image formed
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Answer:
1/f= 1/v-1/u
by this you'll get image distance as 50/3cm i.e position of image is 50/3cm towards right from pole
nature of image = real and inverted
image size=10/3
Hello Dear Soul ❤
Your Answer :
Height of the object, h' = 5 cm
Distance of object from conversing lens, u = 25 cm
Focal length of conversing lens, f = 10 cm
Using lens formula,
1/v - 1/u = 1/f
1/v = 1/f + 1/u
1/v = 1/10 - 1/25 = 15/250
v = 250/15 = 16.66 cm
Also for conversing lens,
h''/h' = v/u { h'' = image height }
h'' = (v/u)× h' = (16.66 × 5) / (-25) = -10/3 = -3.3 cm
Thus, The image is inverted and formed at a distance of 16.7 cm behind the lens and measured 3.3 cm.
Note : Ray diagram of this problem is given in attached file.
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