An object is placed (1) asymmetrically (2) symmetrically, between two plane mirrors inclined at an angle of 50°. Find the number of images formed
An object is placed (1) asymmetrically (2) symmetrically, between two plane mirrors inclined at an angle of 50°. Find the number of images formed
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For two mirrors kept at an angle x, the number of images n is determined by the formula 360/x.
If n turns out to be odd,
We have the following two cases:
Asymmetrically
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Number of images=n
Symmetrically
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Number of images=n-1
And if n turns out to be even,
Number of images= n-1 for all positions of object
Now, coming back to your question,
Here x=50
n=360/x
=360/50
=7.2
Rounding off,n=7
Now,n is odd.
(1) Asymmetrically
number of images=n
=7
(2) Symmetrically
number of images= n-1
= 7-1
=6
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