An object of height 4 cm is placed on the principal
axis at a distance of 20 cm in front of a convex
lens of focal length 30 cm. Find the distance of
image from the lens, its height and nature
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An object of height 4 cm is placed on the principal
axis at a distance of 20 cm in front of a convex
lens of focal length 30 cm. Find the distance of
image from the lens, its height and nature
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Answer:
distance of image is -60cm, Height is 12cm and nature it is virtual and erect.
Explanation:
step by step explanation.
u= -20cm
F = 30cm
v= ?
1/f = 1/v - 1/u
1/30 = 1/v - 1/-20
1/30-1/20=1/v
take LCM then, we get
v= -60cm
M=v/u = height of image/Height of object
-60/-20=height of image/4
height of image= 4×3=12cm