And the modulus and argument of complex no. 2√3i -2
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And the modulus and argument of complex no. 2√3i -2
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Answer:
Correct option is
C
∣z∣=4;amp(z)=
3
2π
∣z∣=2
1+3
=2.2=4
And let α be the argument of the complex number.
Then
tanα=−
3
Now Re(z)<0 and Im(z)>0
Hence,
z=4(
2
−1+
3
i
)
α=π−
3
π
=
3
2π