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Answer:
Step-by-step explanation:
1) given
BP║AC
So, area of ΔABC = area of ΔACP
as 2 triangles on the same base and between the same parallels are equal in area.
arΔABC - arΔAOC = arΔACP - arΔAOC
ar Δ AOB = ar Δ COP
proved
2) area of ΔABC = area of ΔACP
ar Δ ADC + ar Δ ABC = ar Δ ADC + ar Δ ACP
ar quad ABCD = ar Δ APD
proved