answer the question
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
Your material is in the attachment HOPE IT HELPS
Answer:
see explanation
Step-by-step explanation:
let ∅ be x
GIVEN-
(sinx - 2sin³x) / (2cos³x - cosx) = tan x
LHS-
(sinx - 2sin³x) / (2cos³x - cosx)
⇒sinx(1-2sin²x) / cosx[2(cos²x) -1]
⇒sinx(1-2sin²x) / cosx[2(1-sin²x)-1] (as cos²x = 1- sin²x)
⇒ sinx(1-2sin²x) / cosx [2 - 2 sin²x -1]
⇒ sinx(1-2sin²x) / cosx (1-2sin²x)
⇒sinx / cosx (as (1-2sin²x) cancel each other)
⇒tanx
Thus LHS = RHS
Hope this helps.....