answer the question no. 12
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Distance of object (u)= -25cm
Focal length of lens (f)=+10cm
Using lens formula= 1/v-1/u=1/f
1/v=1/f+1/u
1/v=1/10+1/-25
1/v=5-2/50
1/v=3/50
v=50/3=+16.67cm
the image is formed on distance 16.67 cm other side of the lens.
Magnification(m)=h'/h=v/u
Height of image(h')=h×v/u
h'=5×50/3 /-25
h'=5×50/3×1/-25
h'=-10/3cm
h'=-3.33cm
Here,negative sign indicates real,inverted image formed below the principal axis.