Answer this question
show that 8^n cannot end with digit 0 for any natural number n.
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Answer this question
show that 8^n cannot end with digit 0 for any natural number n.
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Therefore, 8^n = 10m,
Where, m is any positive integer.
Now,
(2 * 2 *2)^n = (2 * 5)m
We can see that 2 is a common factor of both the numbers, but 5 is not.
Therefore, our assumption is contradicted.
Thus, 8^n does not end with 0.