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Answer:
[tex] \LARGE{ \underline{\underline{ \pink{ \bf{ANSWER}}}}}[/tex] 1) x = 6 3) x = 35)
Step-by-step explanation:
Step-by-step explanation:
Given :-
i) P(y) = y²-y+1
ii) P(x) = x³
To find :-
Find the values of P(0),P(1) and P(2) for the following polynomials ?
Solution :-
i) Given Polynomial P(y) = y²-y+1 ---------(1)
Put y = 0 in the equation (1) then
=> P(0) = (0)²-(0)+1
=> P(0) = 0-0+1
=> P(0) = 1
The value of P(0) = 1
Put y = 1 in the equation (1) then
=>P(1) = (1)²-(1)+1
=> P(1) = 1-1+1
=> P(1) = 2-1
=> P(1) = 1
The value of P(1) = 1
Put y = 2 in the equation (1) then
=> P(2) = (2)²-2+1
=>P(2) = 4-2+1
=>P(2) = 5-2
=> P(2) = 3
The value of P(2) = 3
ii) Given Polynomial P(x) = x³ ---------(2)
Put x = 0 in the equation (2) then
=> P(0) = (0)³
=> P(0) = 0
The value of P(0) = 0
Put x = 1 in the equation (2) then
=>P(1) = (1)³
=> P(1) = 1
The value of P(1) = 1
Put x = 2 in the equation (2) then
=> P(2) = (2)³
=>P(2) = 2×2×2
=> P(2) = 8
The value of P(2) = 8
Answer :-
I)
P(0) = 1
P(1) = 1
P(2) = 3
(ii)
P(0) = 0
P(1) = 1
P(2) = 8