anyone pls solve this
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Step-by-step explanation
∠1=∠2 SO PT=PS............................1ST EQUATION
ΔNSQ≅ΔMTR
SO ∠NQS =∠MRT
∠PQR =∠PRT
PR=PQ ........................ 2ND EQUATION
FROM 1ST AND 2ND
PT÷PR = PS ÷PQ
ALSO ∠TPQ =∠RPQ .........[COMMON]
ΔPTS IS SMILAR TOΔPRQ