If p(x) = ax2 + bx + c, and a + b + c = 0, then one zero is
a) b/a
b)c/a
c)-b/a
d)-c/a
Please answer Fast.
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If p(x) = ax2 + bx + c, and a + b + c = 0, then one zero is
a) b/a
b)c/a
c)-b/a
d)-c/a
Please answer Fast.
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Step-by-step explanation:
P(x ) = ax² + bx + c
put x = 1
P(1) = a + b + c
but a + b + c = 0
so, P(1) = 0
so, x = 1 is the root of P(x )