A's age is five times as that of B. Ten years later, A's age will be thrice that of B, find A's age.
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A's age is five times as that of B. Ten years later, A's age will be thrice that of B, find A's age.
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Answer:
Step-by-step explanation:
Present age
A=5*B (equation 1)
10 years later
A age will be=A+10
B age will be=B+10
Equation 2:
(A+10)=3(B+10)
Substituting value of A from equation 1:
5B+10=3B+30
5B-3B=30-10
2B=20
B=10
From equation 1=
A=5*B
A=5*10=50
Answer:
60 years
Step-by-step explanation:
Let the present age of B =x
and A age=5x
After ten years B age=x+10
A age=5x+10
A/Q....
3(x+10)=5x+10
3x+30=5x+10
3x-5x=10-30
-2x=-20
x=10
A age=5×10+10
60 years
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