A's age is twice B's; 4 years ago
A was three times as old as B
find their present ages.
.
Share
A's age is twice B's; 4 years ago
A was three times as old as B
find their present ages.
.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Step-by-step explanation:
let, the present age of B = y years
according to question
the present age of A = 2(y)
before 4 years both ages will be
A B
2y-4= y-4
now according to question
A was 3 times of B
but if we multiply 3 on A then both these equations will not equal so we multiply by 3 on B
2y-4=3(y-4)
2y-4= 3y-12
2y+8= 3y (on adding 12 both side )
8years =y( on subtracting 2y both side)
So , the present age of B is 8 years
and present age of A is =16 years
MARK IT BRAINLIEST IF IT HELPS