A's income is 15% more than B's income. Find how much percent B's income is less than A's income.
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A's income is 15% more than B's income. Find how much percent B's income is less than A's income.
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B's income is 13.04% less than A's income.
Given :
To find:
Solution:
Concept to be used:
B's income % as comparison with A's income[tex] = \frac{ \text{Difference \: of \: both \: incomes}}{Income \: of \: A} \times 100 \\ [/tex]%
Step 1:
Write incomes of both A and B.
Let income of B is 100x.
Thus,
A's income is 15% more than B's income.
So,
A's income is 115x.
Step 2:
Find how much percent B's income is less than A's income.
[tex] = \frac{115x - 100x}{115x} \times 100 \\ [/tex]
or
[tex] = \frac{15}{115} \times 100 \\ [/tex]
or
[tex] = 13.04 \\ [/tex]
Thus,
B's income is 13.04% less than A's income.
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So the income of A:
=B's income +(B's income×15%)
100+(100×15%)
100+[100×(15/100)]
100+15
115
Now , B's income is less then A's income by (in Rs):
A's income - B's income
Rs (115-100)
Rs -15
So B's income is less than A's income by (in %)
100×(less in Rs/ A's income )
100×(15/115)
13.04% approx
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