as you cool it down from 241℃ ,at which temperature it solidify
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as you cool it down from 241℃ ,at which temperature it solidify
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given inital temperature Ti=100c
final temperature Tf = 60c
Surrounding temperature =To=20c
A\C Newton law of cooling
dT/dt=K[ti +tf /2-to ]
Tf -Ti /t= K[ti+tf /to ]
40/20 =K[80-20]
[K=1\3]
in the second case tf=30c K=1\3 T=?
100 -30 \t = K[45] = 15
T=70/15= 14\3 =4.6minutes
Therefore time to cool down to 30c in 4.6 minutes