at what separation should two equal charges one coulomb each be placed so that the force between them equal the weight of a 50 kg person
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at what separation should two equal charges one coulomb each be placed so that the force between them equal the weight of a 50 kg person
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By Coulomb's inverse square law,
F==K/r^2 (Because q1=q2=1C)
500=K/r^2
500=9 x /r^2
r^2=18 x
r=4.24264 x meters
r = 4.24 km