Ay Let A = {1,2,3,4,5} , B={2,3,6,7} . Then the no.
of clements in (AXB) n (BXA) is
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Ay Let A = {1,2,3,4,5} , B={2,3,6,7} . Then the no.
of clements in (AXB) n (BXA) is
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Answer:
We have to find out (A × B) ∩ (B × A).
Given that A = {1, 2, 3, 4, 5} and B = {2, 3, 6, 7}
We have to use the identities given below:
1. A ∩ B = B ∩ A
2. (A × B) ∩ (C × D) = (A ∩ C) × (B ∩ D)
According to the 2nd identity,
(A × B) ∩ (B × A) = (A ∩ B) × (B ∩ A)
According to the 1st identity,
(A ∩ B) × (B ∩ A) = (A ∩ B) × (A ∩ B)
Thus,
(A × B) ∩ (B × A) = (A ∩ B) × (A ∩ B)
Now we have to find A ∩ B.
A ∩ B = {2, 3}
So,
(A ∩ B) × (A ∩ B)
⇒ {2, 3} × {2, 3}
⇒ {(2, 2), (2, 3), (3, 2), (3, 3)}
Hence. (A × B) ∩ (B × A) has 4 elements.
|(A × B) ∩ (B × A)| = 4
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