b part please .......
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Then, angle BCA = 90°
(The diameter forms 90° with the Circumference)
Since CD || AB
=> angle DCB = 25° (alternate Angle)
Angle ACD = angle BCA + angle DCB
=> angle ACD = 90° + 25°
=> angle ACD = 115°
Now, join BD. Hence, ACBD becomes cyclic quadrilateral.
We know that opposite angles are supplementary in a cyclic quadrilateral.
=> angle ACD + angle ABD = 180°
angle ABD = 25° + angle CBD
=> angle ACD + 25° + angle CBD = 180°
=> 115 + 25 + angle CBD = 180°
=> angle CBD = 180 - 115 - 25
=> angle CBD = 40°
angle CED = angle CBD (angles formed on same or equal chords with the circumference are equal)
=> angle CED = 40°