Evaluate: ∫ 3ax/(b2 +c2x2) dx
please give the right answer
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(b2 +c2x2) dx please give the right answer
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Answer:
To evaluate the integral, I = ∫ 3ax/(b2 +c2x2) dx
Let us take v = b2 +c2x2, then
dv = 2c2x dx
Thus, ∫ 3ax/(b2 +c2x2) dx
= (3ax/2c2x)∫dv/v
Now, cancel x on both numerator and denominator, we get
= (3a/2c2)∫dv/v
= (3a/2c2) log |b2 +c2x2| + C
Where C is an arbitrary constant