Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the all three ages is 135 years. What is the age of each one of them????????
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Baichung's father is 26 years younger than Baichung's grandfather and 29 years older than Baichung. The sum of the all three ages is 135 years. What is the age of each one of them????????
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Answer:
Step-by-step explanation:
B GRAND FATHER=B FATHER+26
B FATHER=B+29
NOW,
B GRAND FATHER+B FATHER+B=135
SO,
B+29+26=B GRAND FATHER
NOW YOU CAN FIGURE OUT THE QUESTION I GAVE THE MAIN IDEA..
Verified answer
Answer:
Baichung is 17 yrs. old
His father is 46 yrs. old
His grandfather is 72 yrs old
Step-by-step explanation:
Let age of Baichung be x then
According to the question
Baichung's father's age = x + 29
also Baichung's father is 26 years younger than Baichung's grandfather
therefore age of Baichung's grandfather = x + 29 +26
= x + 55
Also the sum of the ages of all three = 135
therefore,
Baichung's age+ Baichung's father's age+ Baichung's grandfather's age= 135
[tex]x + (x + 29) + (x + 55) = 135\\x + x + 29 + x + 55 = 135\\3x + 84 = 135\\3x = 135 - 84\\3x = 51\\x = \frac{51}{3} = 17[/tex]
therefore,
Baichung is 17 yrs. old
His father is x + 29 = 17 +29 = 46 yrs. old
His grandfather is x + 55 = 17 + 55 = 72 yrs old