balance the reaction .AgBr=Ag+Br2 .
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Answer:
[tex] \huge\mathbb\red{Answer:-}[/tex]
2AgBr → 2Ag + Br2
[tex] \huge\mathbb\green{Explanation:-}[/tex]
This is an oxidation-reduction (redox) reaction:
2 Br-I - 2 e- → 2 Br0
(oxidation)
2 AgI + 2 e- → 2 Ag0
(reduction)
AgBr is a reducing agent, AgBr is an oxidizing agent.
Answer:
2AgBr=2Ag+Br2
Explanation:
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