Bus calculated uniform from 18 kilometre per hour to 36 kilometre per hour in 10 seconds calculate the acceleration
Bus calculated uniform from 18 kilometre per hour to 36 kilometre per hour in 10 seconds calculate the acceleration
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Answer:
Step-by-step explanation:
Initial speed = u = 18 km/hr = 5 m/s.
Final sped = v = 36 km/hr = 10 m/s.
acceleration a = (v-u)/t = (10-5)/5 = 1 m/s2
Distance travelled S = u t + (1/2) a t2 = 5×5 + (1/2)×1×52 = 37.5 m.
Answer:
Given parameters
Time taken (t) = 5 sec
Initial velocity (u) =18 km/hour
\(u = \frac{18\times 1000}{60\times 60s}\)
u = 5 m/s
Final velocity (v) =36km/hour
\(v = \frac{36\times 1000}{60\times 60s}\)
v =10 m/s
We need to calculate acceleration and distance traveled
We know that
acceleration a = (v – u)/t
Substituting the given values in the above equation we get,
a = (10 – 5)/5
a =5/5
a = 1 m/s2
We know that distance travelled is calculated by the formula
Distance travelled S = u t + (1/2) a × t2
Substituting the given values in the above equation we get,
S = 5 × 5 + (1/2) × 1 × 52
S = 25 + (1/2) × 25
S = 25 + 12.5
S = 37.5 m
Hence
acceleration a =1 m/s2
Distance travelled S =37.5 m
Step-by-step explanation:
❣️ Gorgeous queen❣️
Answer:
Given parameters
Time taken (t) = 5 sec
Initial velocity (u) =18 km/hour
\(u = \frac{18\times 1000}{60\times 60s}\)
u = 5 m/s
Final velocity (v) =36km/hour
\(v = \frac{36\times 1000}{60\times 60s}\)
v =10 m/s
We need to calculate acceleration and distance traveled
We know that
acceleration a = (v – u)/t
Substituting the given values in the above equation we get,
a = (10 – 5)/5
a =5/5
a = 1 m/s2
We know that distance travelled is calculated by the formula
Distance travelled S = u t + (1/2) a × t2
Substituting the given values in the above equation we get,
S = 5 × 5 + (1/2) × 1 × 52
S = 25 + (1/2) × 25
S = 25 + 12.5
S = 37.5 m
Hence
acceleration a =1 m/s2
Distance travelled S =37.5 m
Step-by-step explanation:
❣️ Gorgeous queen❣️