Bye everyone I will be back at 11am
If NaCl is doped with 10^(-4)mol%of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))
Share
Bye everyone I will be back at 11am
If NaCl is doped with 10^(-4)mol%of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
0 Replies